422 H. CONVEX FUNCTIONS ON RIEMANNIAN MANIFOLDS
STEP 3 (Regularity of the path a). This follows from showing that a
satisfies L (a)= de (x,y). Given any partition {se}~ 0 of [O, 1], we have
N
L d (f3ij (sc-1), f3ij (sc)) :::; L (f3ij).
£=1
Taking the limit ij -t oo, we obtain
N
""d L.1 (a (sc-1), a (sc)):::; i-+oo ,lim L (f3i),
£=1
and hence
L (a) :::; de (x, y).
Since a is a curve in C joining x and y, we conclude
L(a) =de(x,y).
Given any s E (0, 1), there exists an open neighborhood U of a (s) in
M such that C n U is convex. In particular, for 0"1 < 0"2 sufficiently small,
we have a (s + O'i) EC n U for i = 1, 2. Since a has minimal length among
paths in C and since C n U is convex, we have
That is, a is locally length minimizing and hence a is a geodesic of ( M, g).
D
REMARK H.16. Alternatively, in the above proof, one should be able to
minimize length in a space of 'piecewise-short' broken geodesics a la Milnor
[129].
The following proposition gives a connection between connected closed
locally convex subsets and Aleksandrov spaces.
PROPOSITION H.17 (Locally convex subsets of Riemannian manifolds).
Let (Mn, g) be a complete Riemannian manifold with sectional curvature 2:
k. Let C be a connected closed locally convex subset in M. Then, as a length
subspace, C is an Aleksandrov space (with possibly nonempty boundary) with
curvature 2: k.
PROOF. Lemma H.15 implies that C is a complete locally compact length
space. Note that, from the definition of convex set and the Toponogov
comparison theorem for M, we know that C satisfies the local version of the
definition of Aleksandrov space with curvature 2: k. D