- INTEGRAL CURVES TO GRADIENTS OF CONCAVE FUNCTIONS 455
by (H.46). Applying Lemma H.37 to the concave function -f and by ap-
plying the uniqueness of V' f (I' 00 (so)) (i.e., Lemma H.36(iv)), we have
1 V' J (r oo (so)) v oo
JV 00 I = IV' f (r 00 (so)) I and IV' f (r 00 (so)) I - JV 001 •
Since we have proved that any sequential limit of the left-hand side of (H.45)
is the same as the right-hand side, the left limit exists and (H.45) holds. This
proves the lemma. D
4.4. Sharafutdinov's contraction map.
Let C C Mn be a compact connected locally convex set with nonempty
interior and boundary and let f E <!:Wo ( C), where <!:Wo ( C) is defined as in
(H.30). Let Cs~ {y EC: f (y) 2: s }, wheres E [O, !sup], as before. Let
I's : C-+ Cs
be defined by
(H.48) I's (x) ~ { ~x (s)
if f (x) 2: s,
ifj(x)<s,
where 'Yx [f (x), !sup] -+ C is the maximal integral curve for V' f /JV' f 1
2
emanating from x. Note that if x E Cs, then I's (x) = x, so by definition,
the map rs is a retraction..
The following is an analogue of Corollary H.10.
THEOREM H.59 (Sharafutdinov's distance nonincreasing retraction). As-
sume the notations above.
(1) (rs is length nonincreasing) For any s E [O, !sup] and any rectifiable
path a: [O, 1]-+ C, we have
L (a) 2: L (rs o a).
(2) (Continuity in x ands) The map
r: C x [O,fsup]-+ C,
defined by
r(x,s) ~rs(x),
is continuous.
PROOF. (1) From the definition of rectifiable path, it suffices to show
that for x, y E C and s E [a, b],
(H.49) de (rs ( x) , rs (y)) ~ de ( x, y).
Without loss of generality we may assume f (x) ~ f (y). There are three
cases to consider.
(i) Ifs~ f (x), then rs (x) = x and rs (y) = y, so that
de (I's (x) ,rs (y)) =de (x,y).