1547845830-Classification_of_Quasithin_Groups_-_Volume_II__Aschbacher_

10.3. THE FINAL CONTRADICTION 757

L2(2m) with m 2 2. However the embedding K < Iz does not occur in the list of
A.3.14, so we conclude that Kz = Jz. Therefore KE .Cj(G, T) with M+ = Na(Kz)·
Thus the hypotheses of Theorem 10.0.l are satisfied with Kin the role of "L". As
K/02(K) is A5 rather than £ 3 (2), 10.2.13 applied to Kin the role of "L" supplies

a contradiction. This contradiction completes the proof of Theorem 10.0.1.