102 8. FIRST SERIES OF IMPLICATIONS
f B
FIGURE 8.3
for z E 1, we see that it is sufficient to establish (8.1.6) and (8.1.7) for the case
where I is a hyperbolic line in D and D is bounded.
Assume now that this is the case and let D' and 1' be the images of D and 1
under
Z - Z 1
w=g(z) = --.
Z - Z2
Let f map H conformally onto D'. Again f extends to a homeomorphism of H
onto D' and we may assume that f(O) = 0 and f(oo) = oo.
Now D' is a K-quasidisk and 1' is the image of the positive imaginary axis
under f. Hence if w E 1', then w = f(iy) for some 0 < y < oo and
(8.1.8) s = 1y If' (it) I dt ::::; C1 dist(!( i y ), aD') = C1 dist( w, aD')
by Lemma 8.1.2 where s denotes the arclength of 1' between 0 and w. Let h = g-^1.
Then
length(/)= f lh'(w)l ldwl = lz1 - z2 1 J 1 ldwl
"I' "I' w - 1 12
(^00 ds
= lz1 - z2I lo lw(s) - 112 ,
where w = w( s) is the arclength representation for 1'. If we let
s ---C1
0 - C1+1 '
then for 0 < s ::::; so,
1
lw(s) - ll ::::>: 1-lw(s)I ::::>: 1 - s ::::>: cl+ 1 ,
while for s 0 ::::; s < oo,
lw(s) - ll ::::>: dist(w(s), aD') ::::>: ~
C1
by (8.1.8) since D c R^2 implies that
1 = g(oo) ej_ D'.
Thus
r= ds ro 1= c2
lo lw(s) - 112 ::::; lo (c1+1)2 ds + so s; ds = 2c1(c1+1) = c2