286 Difference Schen1es for Elliptic Equations
where E stands for the identity operator.
The self-adjointness of the operator A = A 1 + A 2 can be proved by
exactly the same reasoning as in Section 2 with further reference to some
properties such as
0
A~= A°'> 0, for y E S.h.
To make sure of it, it suffices to calculate the row sum with CY= 1 for fixed
i 2 = 1, 2, ... , N2 - 1. The outcome of this is
N1-l N1-l
L (A1 Y)i, V; 1 hi= - L (a1 YxJx,,i1 V; 1 h1
N1-l
L Y; 1 (a1 v:vJ.,,,,i, h1
i I= I
N1 -I
= L Y;, (A1 v);, h1.
i 1 =I
Multiplying this identity by h 2 and summing over i 2 = 1, 2, ... , N 2 - 1, we
establish (A 1 y, v) = (y, A 1 v) and, in a sin1ilar way, (A 2 y, v) = (y, A 2 v),
yielding
(Ay, v) = ((A 1 + A2) y, v) = (y, Av).
By definition, this means A* = A.
- Equations with mixed derivatives. In this section we consider problem
(23) involving the elliptic operator L with mixed derivatives
2
(30) Lu= L Laf3 'U,
a,(3=1
assuming the ellipticity conditions
2 2 2
(31) c 1 L ~~ < L kL~μ(x) ~°' ~f3 < c 2 L ~~' x E G,
a,(3=1 a=!
to be valid, where c 1 > 0, c 2 > 0 are constants and e = (~ 1 , ~ 2 ) is an
arbitrary vector. Setting first ~ 1 = 1, ~ 2 = 0 and then ~ 1 = 0, ~ 2 = 1 it is
not difficult to check that
CY= 1,2.