1549312215-Complex_Analysis_for_Mathematics_and_Engineering_5th_edition__Mathews

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8.1 • THE RESIDUE THEOREM 295


  • EXAMPLE 8 .4 Find the residue off (z) = " <^0 ;<"•) at zo = O.


Solution We write f (z) = ; ";:~ ::. Because z^2 sin 7rZ has a zero of order 3


at zo = 0 and 7rcos(7rzo) "# 0, f has a pole of order 3 at zo. By part (iii) of
Theorem 8.2, we have


1 d^2

Res[f,O] = - 21 Jim -d 2 7rzcot(7rz)

.z-o z

= -
2

1
lim dd [7r cot (7rz) - 71"^2 z csc^2 ( 7rZ)]
z-+0 Z
= -
2

1
lim [-7r^2 csc^2 (7rz) - 7r^2 { csc^2 (7rz) - 27rz csc^2 (7rz) cot (?Tz)} J
z-+O
= 71"^2 lim (7rzcot (7rz) -1) csc^2 (7rz)
z-o

= 7r^21 1m. 7rzcos(?Tz)--~""""--~""'" - sin(?Tz)
,, .... o sin^3 (7rz)
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