1549312215-Complex_Analysis_for_Mathematics_and_Engineering_5th_edition__Mathews

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324 C HAPTER 8 • RESIDUE THEOltY



  • EXAMPLE 8.23 Evaluate P.V. Jo"'° x(::i) dx, where 0 <a< 1.


Solution The function f (z) = z(;: 1 ) has a nonzero pole at the point - 1, and
the de nominator has a zero of order at most 1 (in fact, exactly 1) at the origin.
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