1549380323-Statistical Mechanics Theory and Molecular Simulation

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Phase space and partition function 141

The link between the macroscopic thermodynamic properties in eqn.(4.2.6) and
the microscopic states contained inQ(N,V,T) is provided through the relation


A(N,V,T) =−kTlnQ(N,V,T) =−

1


β

lnQ(N,V,β). (4.3.17)

In order to see that eqn. (4.3.17) provides the connection between the thermodynamic
state functionA(N,V,T) and the partition functionQ(N,V,T), we note thatA=
E−TSand thatS=−∂A/∂T, from which we obtain


A=E+T


∂A


∂T


. (4.3.18)


We also recognize thatE =〈H(x)〉, the ensemble average of the Hamiltonian. By
definition, this ensemble average is


〈H〉=


CN



dxH(x)e−βH(x)
CN


dx e−βH(x)

=−


1


Q(N,V,T)



∂β

Q(N,V,T)


=−



∂β

lnQ(N,V,T). (4.3.19)

Thus, eqn. (4.3.18) becomes


A+



∂β

lnQ(N,V,β) +β

∂A


∂β

= 0, (4.3.20)


where the fact that


T

∂A


∂T


=T


∂A


∂β

∂β
∂T

=−T


∂A


∂β

1


kT^2

=−β

∂A


∂β

(4.3.21)


has been used. We just need to show that eqn. (4.3.17) is the solution to eqn. (4.3.20),
which is a first-order differential equation forA. Differentiating eqn. (4.3.17) with
respect toβgives


β

∂A


∂β

=


1


β

lnQ(N,V,β)−


∂β

lnQ(N,V,β). (4.3.22)

Substituting eqns. (4.3.17) and (4.3.22) into eqn. (4.3.20) yields



1


β

lnQ(N,V,β) +


∂β

lnQ(N,V,β) +

1


β

lnQ(N,V,β)−


∂β

lnQ(N,V,β) = 0,

which verifies thatA=−kTlnQis the solution. Therefore, from eqn. (4.2.6), it is clear
that the macroscopic thermodynamic observables are given in terms of the partition
function by

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