1549380323-Statistical Mechanics Theory and Molecular Simulation

(jair2018) #1
The ideal boson gas 441

V


P


T 1


T 2


T 3


Fig. 11.5Plot of the isotherms of the equation of state in eqn. (11.6.43). HereT 1 > T 2 > T 3.
The dotted line connects the transition points from constant to decreasing pressure and is of
the formP∼V−^5 /^3.


the classical ideal gas. This is likewise in contrast to the fermion idealgas, where
asT →0, the pressure remains finite. For the boson gas, asT →0, the pressure
vanishes, in keeping with the notion of an effective “attraction” between the particles
that causes them to condense into the ground state, which is a state of zero energy.
Other thermodynamic quantities follow from the equation of state.The energy can
be obtained fromE= 3PV/2, yielding


E=





3
2

kTV
λ^3 g^5 /^2 (1) ρ > ρ^0 ,T < T^0
3
2

kTV
λ^3 g^5 /^2 (ζ) ρ < ρ^0 ,T > T^0

, (11.6.44)


and the heat capacity at constant volume is obtained fromCV = (∂E/∂T)v, which
gives


CV
〈N〉k

=





15
4

g 5 / 2 (1)
ρλ^3 T < T^0
15
4

g 5 / 2 (ζ)
ρλ^3 −

9
4

g 3 / 2 (ζ)
g 1 / 2 (ζ) T > T^0

. (11.6.45)


The plot of the heat capacity in Fig. 11.6 exhibits a cusp atT=T 0. Experiments
carried out on liquid^4 He, which has been observed to undergo Bose–Einstein con-
densation at aroundT=2.18 K, have measured an actual discontinuity in the heat
capacity at the transition temperature, suggesting that Bose–Einstein condensation is
a phase transition known as aλtransition. By contrast, the heat capacity of the ideal

Free download pdf