10.2.6 Subsequences and Cluster Points 115Find all cluster points of the following sequences. Then use Corollary
2.6.10 or Theorem 2.6.17 to tell whether the sequence converges.{
(a) 2,^1 1 1 1} {1 1 1 1 }
2
,3,
3,4,
4,5,
5, ... (b) 1,
2,2,1,
3,3,1,
4, 4,1,
5,5,···
{
(c) 1, -2,^1 1 1 1 }
3, 4, -5,
6, 7, -8, g' 10 , -11,
12, · · ·(d) {(-1)n5+~} (e) {(-1r(5+~)}(f) { 5 + (-~r} (g) { sm. n'lf}
6
(h) {cos n
37r} (i) {tan
4
:}- Prove Theorem 2.6.17 (a).
- Give an example of a sequence that has exactly 100 cluster points.
- Show that a sequence can have infinitely many cluster points, by giving
an example of a sequence that has every natural number as a cluster
point.
14. Prove that if a monotone sequence { Xn} has a cluster point x (finite or
infinite), then Xn ---+ x.15. Prove that a sequence that is not bounded above has a subsequence di-
verging to +oo, and a sequence that is not bounded below has a subse-
quence diverging to -oo.- Prove that a sequence diverges if and only if it either has more than one
cluster point or is unbounded. - Prove that a sequence { Xn} converges to a real number L if and only if
every subsequence of { Xn} has a subsequence converging to L.
18. Prove that a sequence {xn} has no convergent subsequence{::} lxnl ---+ oo.- Finish the proof of Theorem 2.6. 18 by proving Case 2.
- Use subsequences to prove that Vx E IR, {sin nx} diverges unless x
k'lf for some k E N. [Hint: Assume sin nx ---+ L. Case 1: L -:/= 0. Show
cos nx ---+ ~ by using 2 cos nx sin nx = sin 2nx ---+ L. Take limit of both
sides of cos 2nx = cos^2 nx - sin^2 nx to get L^2 < 0. Case 2: L = 0. Then
cos^2 nx = 1 - sin^2 nx ---+ 1. Take the limit of both sides of sin(n + l)x =
sin n cos x + cos nx sin x to get a contradiction.] Finally, use the above
results to prove that {cos nx} diverges unless x is an even multiple of 7r.