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2.7 Cauchy Sequences 117
First show^14 that Vu, v E JR, ..jUV :::; u ; v and equality holds <¢=> u = v.
Use this to show that a< Y1 < Y2 < · · · < Yn < Xn < · · · < X2 < X1 < b.
a+b
Also, show that 'Vn EN, lxn -Ynl <
2
n - l. Use these results to cbnclude
that {xn} and {yn} converge and have the same limit. This common limit
is called the arithmetic-geometric mean of a and b.
- 7 Cauchy Sequences
It is often possible to prove that a sequence converges without knowing its
actual limit. The monotone convergence theorem provides one tool for doing
that. The "Cauchy criterion" we are about to study is another.
Definition 2.7.1 A sequence {xn} is a Cauchy sequence if it satisfies the
"Cauchy criterion:"
The significance of the Cauchy criterion is that, unlike Definition 2.1.4, this
criterion makes no reference to a limit "L." Thus, it can prove useful when
we do not know in advance whether a sequence has a limit, or whether it is
monotone. We shall prove shortly that every Cauchy sequence converges.
Theorem 2.7.2 Every convergent sequence is a Cauchy sequence.
Proof. Suppose { Xn} converges, say Xn --t L. Let c: > 0. Then :l no E N 3
€
n ::'.': no => I Xn - LI < 2. Then
€ €
m , n ::'.': no => lxm - LI < 2 and lxn - LI < 2
=> lxm - LI + lxn - LI < €
=> lxm - LI + IL -Xnl < €
=> lxm - L + L - Xnl < € by the triangle inequality
=> lxm - Xnl < €.
Therefore, {xn} is a Cauchy sequence. •
The next t heorem should remind you of Theorem 2.2.10 for convergent
sequences. The proofs are almost the same.
Theorem 2.7.3 Every Cauchy sequence is bounded.
- See Exercise 1.2-B.10.