6.4 Mean-Value Type Theorems 323
Theorem 6.4.3 (Mean Value Theorem, "MVT") Suppose f: [a, b] -t JR
is differentiable on (a,b), and continuous on [a,b], where a< b. Then :Jc E
(a, b) 3 f'(c) = f(b~ =~(a).
y
f(b)-j(a)
(b,f(b)) '} y=f(x)+ b-a (x-a)
____ J f(b)-f(a)
a c c
Figure 6.7
I I
I I
b x
Proof. Suppose f is differentiable on (a, b), and continuous on [a, b], where
a< b. Define a new function hon [a, b] by
h(x) = f(x) - f(a) - f(b~ =~(a) (x - a). (3)
Then h differs from f by a first degree polynomial function in x, so h is
continuous wherever f is and differentiable wherever f is. Moreover,
f(b) - f(a)
h(a) = f(a) - f(a) - b _a (a - a) = 0, and
h(b) = f(b) - f(a) - f(b) - f(a) (b - a)
b-a
= f(b) - f(a) - [f(b) - f(a)]
= 0.
Thus, h(a) = h(b), and h satisfies all the hypotheses of Rolle's theorem.
Hence, by Rolle's theorem, 3 c E (a, b) 3 h'(c) = 0. Now, from (3),
h'(x) = f'(x) _ f(b) - f(a).
b-a