7.3 The Integral as a Limit of Riemann Sums 373
Proof. Suppose f is defined and bounded on [a, b]. Then 3M > 0 3 \:/x E
[a, b], lf(x)I :::; M.
Part 1 (~):Suppose that Ve> 0, 36 > 0 3 \:/partitions P of [a,b],
llPll < o::::? S(f, P) -S_(f, P) < c. Let c > 0. For the o > 0 guaranteed by our
b-a
hypothesis, choose any n E N 3 --< o, and let P be the partition of [a, b]
n
into n subintervals of equal l ength. Then llPll = b - a < o, so by hypothesis,
n
S(f, P) -S_(f, P) < c. Hence, by Riemann's criterion for integrability (7.2.14),
f is integrable over [a, b].
Part 2 (::::?): Suppose f is integrable over [a,b]. Let c > 0. By Riemann's
criterion (Theorem 7.2.14), 3 partition P = {xo,x 1 ,x2, · · · ,xn} of [a,b] 3
- c
S(f, P) -S_(f, P) < "2.
Let this partition remain fixed throughout the remainder of the proof.
c
Leto= 16nM·
Now, consider any partition Q of [a, b] such that II Qll < o. Let R=Q UP.
If R has one more point than Q, then (see Exercise 1)
(1)
S_(f, R) -S_(f, Q):::; 2MllQll - (-2M)llQll = 4MllQll (2)
Since R has at most n points not in Q, we can use mathematical induction
to show that
S_(f, R) - S_(f, Q) :::; 4nMll Qll
< 4nMo
c
=4nM·--
c 16nM
- 4
Now, R 2 Q and R 2 P. Thus, by Theorem 7.2.4,
c
S_(f, P) - S_(f, Q) :::; S_(f, R) - S_(f, Q) <
4
, so
c
-S_(f, Q) < -S_(f, P) + 4·
Using a similar argument with upper sums, we can show that
- c
S(f, Q) < S(f, P) +
4
- c
.
(3)
(4)