8.3 Series with Positive and Negative Terms 485
Theorem 8.3.16 A series converges absolutely if and only if each of its sub-
se'ries converges (absolutely).
Proof. Part 1 ( =>): Suppose I: an converges absolutely, and let I: ank be
a subseries. Then, Vm EN, m::; nrn, so
m nm ex:>
L lank I ::; L lakl ::; L lakl·
k=l k=l k=l
Thus, the sequence of partial sums of the subseries I: lank I is bounded
above, so the subseries I: lank I converges absolutely.
P art 2 (-¢:::): Suppose every subseries of the series I: an converges. Then ,
both the series of positive terms and the series of negative terms of I: an
converge, so both I: a;i and I: a;;: converge. By Theorem 8.3.10, this implies
that I: an converges absolutely. •
EXERCISE SET 8.3
- Prove the assertions made in Example 8.3.6.
- Prove Lemma 8.3.9.
- Prove Theorem 8.3.10 (d).
111111111111 - Prove that the series - - -+ - - -+ - - -+ - - -+ - - - + - - - +
2 2 4 4 4 4 8 8 8 8 8 8
~ -~ + J_ - · · · converges conditionally, and find its sum.
8 8 16
11111 1 1 1 - Prove that the series - - - + - - - + - - - + · · · + - - - + · · ·
2 3 4 9 8 27 2k 3k
converges to ~. Does it converge absolutely or conditionally?
- Determine whether each of the following alternating series converges ab-
solutely, converges conditionally, or diverges. In case of convergence, find
an integer no such t hat n ~no=> IS -Snl < .01.
oo (-1r+i oo (-1)n+i
(a) I: (b) I: --
n=l ..JnTI n=l 3n + 4
(^00) ( -1) n+^1 sin n
(e) n~l n2
oo (-l)n+ln3
(d) n~l (n + 2)!
( f) f ( -1 r ln n
n=l n