3.4. Takesaki 's Theorem 77
Exercise 3.3.5. If 7r: A -+ C and (}: B -+ D are *-homomorphisms, prove
that there is a unique *-homomorphism 7r Q9 (} : A Q9 B -+ C Q9 D such that
7r Q9 (}(a Q9 b) = 7r(a) Q9 (J(b).
Exercise 3.3.6. Prove that JIB(.€^2 ) 0 lIB(.€^2 ) c JIB(.€^2 Q9 £^2 ) (see Lemma 3.3.9)
is not dense in norm.
3.4. Takesaki's Theorem
This section is devoted to the fact that 11 · llmin is really the smallest possible
C*-norm on A 0 B. The main ingredient in the proof is Proposition 3.4.7
- for any pair of functionals <p E A, 'I/; E B and any C* -norm 11 · 11 a on
A 0 B, the natural linear functional cp 0 'I/; is automatically continuous with
respect to II· Ila· There are two routes to this result. We first give Takesaki's
original argument - a lovely display of soft analysis - then, at the end of the
section, we sketch an alternate proof based on excision.
The first lemma may already be familiar. If not, it is a fact worth
remembering.
Lemma 3.4.1. Let S(A) denote the state space of a C*-algebra A. Assume
that S C S(A) is a set of states with the property that for each self-adjoint
a EA we have
llall = sup{lcp(a)I}.
cpES
Then the weak-* closed convex hull of S contains S(A) (hence is equal to
S(A) when A is unital).
Proof. Let S denote the closed convex hull of S and assume there is a state
'I/; which doesn't belong to S. By the Hahn-Banach Theorem we can find
a E A and a real number t such that Re(cp(a)) < t < Re('l/;(a)) for every
cp E S. (Recall that A is the dual of A* with respect to the weak-* topology.)
. Replacing a with its real part, we may assume a is self-adjoint. Note that
if a happened to be positive, then we would have our contradiction since
'l/;(a) ~ llall· So the trick is to replace a with a positive element. In the
unital case one considers a+ llalllA 2::: 0 and notes that
0 ~ <p(a + llalllA) = <p(a) + llall < t + liall < 'l/;(a + iialilA)·
Hence
ila+ilalllAll = sup{l<p(a+ilalilA)i} ~ t+llali < 'l/;(a+iialilA) ~ iia+iialllAll,
cpES
which gives the contradiction. In the nonunital case one passes to unitiza-
tions and applies the argument above. 0