The Laplace Trans/ arm Method
EXAMPLE 2 Using the Laplace Transform to Solve a
Nonhomogeneous Linear Differential Equation
245
Find the general solution of the nonhomogeneous linear differential equation
y" + y' - 2y = x^2 - 1
using the Laplace transform method.
SOLUTION
Apply the Laplace Transform to the Differential Equation
Successively taking the Laplace transform of the given equation, using the
linearity property of the Laplace transform, replacing L'.[y"(x)] by the expres-
sion we obtain from equation (2) with n = 2, and replacing L'.[y'(x)] by the
expression we obtain from equation (2) with n = 1, results in
L'.[y" + y' - 2y] = L'.[x^2 - 1]
L'.[y"(x) ] + L'.[y'(x)] - 2.L'.[y(x)] = L'.[x^2 ] -L'.[1]
(5) (-y'(O) - sy(O) + s^2 L'.[y(x)]) + (-y(O) + sL'.[y(x)])-2.L'.[y(x)] =
2
s^3 - ~. s
Solve the Algebraic Equation for L'.[y(x)]
Letting A= y(O) and B = y'(O) and solving for L'.[y(x)], yields
2 1
A(s + 1) + B + 3 - -
(6) L'.[y(x)] = s s
s^2 + s - 2
A(s+l)+B 2
= (s + 2)(s - 1) + -s3-(s-+-2)-(s---l-)
1
s(s + 2)(s - 1)'
Expanding the right-hand side of this equation using partial fraction expan-
sion and combining like terms, we find
(7)
C1 C2 1 1 1
L'.[y(x)] = - + - - - - - - -
s + 2 s - 1 4s 2s2 s3
where c 1 = (4A - 4B - 1)/12 and c 2 = (2A + B + 1)/3 are arbitrary real
constants, since A and B are arbitrary real constants.