1550251515-Classical_Complex_Analysis__Gonzalez_

(jair2018) #1
Sequences and Series 209


  1. Consider the series


2
2 1 2 1 3 1 3m
+ 3 Z + 3 Z + 22. 3 z + ... + 2sm-13m z
1 z3m+l 1 z3m+2
+ 2sm-l3m+i + 2sm3m+1 + · · ·
Here

I a:::l I =


3
' I ::::~ I =

2
' I ::::: I =

4

Hence, by (4.11-10), R = ij3.2.4 = 2-ij3. Otherwise: As m-+ oo, we obtain


1
-+ --
2-ij3'

3m+v -----+ (^1) -- 1
2sm-13m+1 2-ij3'
Hence, by (4.11-4), R = 2-ij3.


6. Consider the series 2=: CnZn, where {en} is the Fibonacci sequence,


defined by co = 0, c1 = 1, and Cn = Cn-l + Cn-2 for n ~ 2. It can be shown
by mathematical induction that Cn = (an -(3n )/VS, where a =^1 / 2 (1 +VS)


and (3 =^1 / 2 (1 - VS). Hence

I


Cn I an-(3n l-((3/a)n
Cn+l = an+l - (3n+l = a - ((3/a)n(3

But lf3/al = (VS - 1)/( VS+ 1) < 1. Thus ((3/a)n -+ 0 as n-+ oo, and
we get


R=~=%(v'5-1)
a

Note As stated before, a series of the form


can be written as 2:: anz^1 n by letting z-a 0 = z^1 • If the disk of convergence
of the last series is lz^1 I < R, then the region of convergence of the given
series is the disk lz - zo I < R.


Theorem 4.23 (Identity Principle for Power Series) Let f(z) = 2=: anzn


for lzl < Ri and g(z) = 2:: bnzn for lzl < R2· If f(z) = g(z) for all


z E N 0 (0), where 0 < 5 < min(R 1 , R2), or if J(zk) = g(zk), where {zk} is


a sequence of points in N5(0) such that zk -+ 0 as n -+ oo, then an = bn

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