228 Chapter 5
w-z1 =M(z-z1)
where M = a/d = a^2 • It is an easy matter to check that this multiplier
again satisfies (5. 7-5).
In the case c "# 0, H = 0 the transformation has a double finite fixed
point z 1 = (a - d)/2c, and the relationship between z - Z1 and w - w1
is given by
1 1
---= --±c
W - Z1 Z - Z1
In fact, we have
az + b az 1 + b z - z1
w-z1= --- =
CZ + d CZ1 + d (CZ + d)( CZ1 + d)
But
a-d a+d
CZ1 + d = --+ d = --= ±1
2 2
since H = 0 implies that a + d = ±2. Hence
1 =±cz+d
W -Z1 Z - Z1
= ± c( Z - Z1) + CZ1 + d
z-z1
1
= ±c+--
z -Z1
(5.7-7)
Note If the image of the point z = p is w = 0, and that of the point
z = q is w = oo, the bilinear transformation can be written as
z-p
w=k--
z-q
where the value of the constant k can be determined if the image of a third
point is given.
Example Suppose that the points 0, oo, i are given as the images of the
points 1, -1, oo, respectively. Then k = i, and the transformation is
. z-l
w=i--
z+l
5.8 Classification of the Bilinear Transformations
First we consider the case where the transformation has two finite distinct