Elementary Functions 265
multiplicity. At any such pole (3 we have P((J) f:. 0, Q((J) = O, so R((J) =
P((J) / Q((J) = oo. Hence R( z) has n zeros and m poles in C, counting
multiplicities.
The definition of w = R(z) is extended to the point oo by means of
the following.
Definition 5.2 Let R(l/z) = R 1 (z). Then we define
R(oo) = Ri(O)
Since
Ri(z) = ao + ai(l/z) + · · · + an(l/zn)
bo + b1(l/z) + · · · + bm(l/zm)
m-n aoz n·+ aiz n-1 + + · · · an
=z
bozm + b1zm-l + · · · + bm
if m > n, then R(oo) = R 1 (0) = 0, so in this case oo is a zero of R(z) of
order m - n; if m = n, then R( oo) = Ri (0) = an/bm, so oo is neither a
zero nor a pole of R(z); finally, if m < n, then R(oo) = R 1 (0) = oo, so in
this case oo is a pole of R( z) of order n - m.
Thus, counting the total number of zeros and poles of R( z) in C*, we have
Number Number
Case of zeros of poles
m>n n+(m-n)=m m
m=n n m
m<n n m+(n-m)=n
We see that in any case the number of zeros of R(z) in the extended
complex plane equals the number of its poles. It we denote that number
by p, we have p = max(m,n). The number pis called the order of the
rational function.
Examples
- For the function w = (z^4 - 1)/(z^2 + 4) we have p = max(2,4) = 4, so
it has in C* four zeros: 1, -1, i, -i, and four poles: 2i, -2i, oo, oo.
2. For w = (z^2 - 9)/(z^3 - 1), p = 3 so it has three zeros: 3, -3, oo and
three poles: 1, 'f], "7^2 ("7 = e^2 '1ri/^3 ).