Elementary Functions 301
w = arcsinz = 1/ 2 7r =i= iLog(z + ~) + 2h (5.25-3)
To choose a principal branch for arc sin z we select that which will give
w = 0 for z = 0. This is accomplished by taking k = 0 and the positive sign
in the second term on the right of (5.25-3). Thus, denoting the principal
branch by Arcsinz, we have
w = Arcsinz = %7r + i Log(z + ~)
and introducing this notation in (5.25-3), we have
{
Arc sin z + 2k7r
arcsinz =
-Arcsinz + {2k + 1)7r
(5.25-4)
(5.25-5)
The reader will note that arc sin z is defined for all finite values of z, since
z + .../z^2 - 1 f= 0 for all z.
In a similar manner, any solution of the equation cos w = z for given
z E C is a value of the multiple-valued inverse cosine, denoted
w = arccosz or w = cos-^1 z
Since cos w = 'sin{% 7r - w ), we have
w = arccosz =^1 / 2 7r - arcsinz
= ±iLog(z + ~)+2h {5.25-6)
The principal branch of this function is defined by
w = Arccosz = -iLog(z + ~) {5.25-7)
On this branch we have ArccosO =^1 / 2 7r, Arccosl = 0, and so on.
As to the inverse hyperbolic sine, we write w = sinh-^1 z to denote
any value of w such that sinh w = z. The last equation is equivalent to
s1n iw = iz, so
w=sinh-^1 z= -iarcsiniz
= { Log{z + .Jz2+i) + 2hi
- Log{z + .Jz2+i) + {2k + l)7ri
{5.25-8)
The principal branch of the inverse hyperbolic sine is defined to be
w = Sinh-^1 z = Log(z + Jz^2 +1) (5.25-9)
For this branch we have Sinh-^1 0 = O, Sinh-^1 i = %7ri, and so on.