1550251515-Classical_Complex_Analysis__Gonzalez_

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18 Chapter^1

the reals. We recall that, in general, by a linear system (or vector space)


over a commutative field F = {a, (3, ... } is meant a set of elements X =

{x,y,z,. .. } together with an equal relation among its elements, a binary

operation in X called addition, and a multiplication of the elements of X
by those of F, satisfying the following conditions:



  1. x + y is uniquely defined and x + y E X.

  2. x + y = y + x.

  3. (x + y) + z = x + (y + z).

  4. There exists an element () E X such that x + () = x for all x E X.

  5. For every x E X there exists an element, denoted -x, such that
    x+(-x) = B.


6. For every x EX and every a E F, the product ax is uniquely defined

and ax EX.



  1. a(f3x) = (af3)x.

  2. (a+,B)q; = ax+,Bx.

  3. a(x + y) = ax+ ay.

  4. μx = x, where μ is the unit of F.


It is clear that the complex number system C satisfies all of conditions 1

to 10, with F the commutative field of the reals.


The elements x 1 , x2, ... , Xn of X are said to be linearly independent


if the equation


aix1 + azXz + · · · + anXn = 0


where ak E F, implies that ak = 0 (k = 1, 2, ... , n). X is of dimension n

( n ~ 1) if there are in X n linearly independent elements x 1 , ... , x n and


if any element x E X can be expressed in the form


X = f31x1 + · · · + f3nXn


with /3k E F (k ~ 1, .. ., ii). The set {xi,xz,.. .,xn} is then called a

basis in X.

The set {u1,u 2 }, where u 1 = (1,0) and u 2 =(0,1), is a basis in C, since

r1 u1 + r2u2 = (r1, 0) + (0, r2) = (r1, r2) = (0, 0)


implies that r 1 = r2 = 0, and we have already seen that for any complex
number (a, b) we have


(a, b) = au1 + bu2


Thus the complex number system is of dimension two over the reals.
However, C is of dimension one over itself.
An algebraic system A is said to be an algebra over the field F if A
is a ring and also a vector space over F, where the ring addition is the

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