500 Chapter^7
1. f is defined for ( on a contour C and for z in an open set A: i.e., f
is defined on C x A.
2. lf(z,()I :5 M (a constant) for all (z,() EC x A.
3. For each ( E C, f is analytic in A.
4. For each z E A, f is continuous on C.
Then
F(z) = j f(z, () d( (7.27-1)
c
is analytic in A, and
F'(z) = j :z J(z, () d( (7.27-2)
c
Proof Let ')': u - z = reit,o :5 t :5 27!', with r small enough so that 'Y* U
Int 'Y* CA (Fig. 7.28). Since f, as a function of z, is analytic in A, we have
f(z,() = ~ J f(u,()du
27l'i u - z
(7.27-3)
"(
by the classical Cauchy's formula. Also, we have by (7.21-2),
~f(z,() = ~ J f(u,()du
oz 27l'i ( u - z )2
(7.27-4)
"(
By using (7.27-3) in (7.27-1), we get
F(z) = ~ Jd(J J(u,()du
27l'i u - z
(7.27-5)
c "(
h+h
u\0
A c
Fig. 7.28