1550251515-Classical_Complex_Analysis__Gonzalez_

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534 Chapters

by making use of Corollary 8.1.


  1. To expand f(z) = (1 + z)P in powers of z, where pis a given complex
    number (in particular, a real number), and the notation (1 +z)P stands for
    its principal value, namely, exppLog(l + z). This function is analytic in


D = C --{x: -oo < x:::; -1}, except when pis a nonnegative integer, in

which case f is analytic in C, or when pis a negative integer, in which case

f is a rational function with a pole at -1, and so analytic in C-{-1}. Since

jCn)(z) = p(p - 1) · · · (p - n + 1)(1 + z)P-n


we get


f(n)(O) = p(p - 1) · · · (p - n + 1) = n! (~)


by introducing the notation


(


p) = p(p - 1) · .. (p -n + 1)
n n!

for n = 1, 2, ...


Thus noticing that f(O) = 1, we obtain the expansion


(8.3-12)

called the binomial series. The series reduces to a polynomial when pis a

nonnegative integer since then (!) = 0 whenever n > p. Except for this
elementary case, we have R = 1, i.e., the resulting infinite series converges


on the unit disk lzl < 1.


  1. To expand f(z) = Arcsinz in power of z. Since f'(z) = (1-z^2 )-^112
    (principal value), we see that the given function is analytic in C-{-1, 1}.
    By using the binomial series to expand f'(z), we get


(1 -· z2)-l/2 = 1+f(-1li)c-z2r=1 + ~ z2 + 1. 3 z4 + ...
n=l n 2 2 · 4

valid for lzl < 1. Now integrating along a rectilinear path from 0 to z

(lzl < 1) we have, recalling that ArcsinO = O,


co (-1/ ) z2n+1
Arcsinz = z + l:C-l)n^2 --

n=l n 2n + 1


valid for lzl < 1.

1 z^3 1·3 z^5


=z+23+2.45+"· (8.3-13)

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