Sequences, Series, and Special Functions 595
Fig. 8.9
For t E Ci we have
1 1
=------
t - z. (t - a) - (z - a)
1 1 ~ (z - a)n (8.18-4)
= t-a 1-(z-a)/(t-a) = ~ (t-a)n+l
where the series representation of the right is valid since for t E Ci we have
I
z-a I p
t-a = R' < l
From (8.18-4) it follows that
f(t) = ~ f(t) (z - a)n
t - z L.J n=O (t - a)n+i
(8.18-5)
Since f(t) is analytic for t E Ci, it is continuous on Ci, so there is a
constant Mi > 0 such that lf(t)I <Mi for all t E Ci. Hence
jict) (;~ -:i)~:i I < ~: ( ~, r
which shows, on applying the Weierstrass M-test, that for each z the series
in (8.18-5) converges uniformly with respect to t for t E Ci. Thus, by
Corollary 8.1, we have
_1 jf(t)dt=~(z-a)nf f(t)dt
27l'i t-z L.J 27l'i (t-a)n+i
01 n=O 01
00
(8.18-6)