Singularities/Residues/ Applications 677
which gives an alternative method (often advantageous) for the evaluation
of an integral in terms of the residue of the integrand at infinity.
Example To evaluate Ic+(z^3 + 2)/(z^4 + 1) dz, where c+: z = 2eit, 0 ~
t ~ 271".
The integrand has simple poles at the points ak (k = 1,2,3,4), where
at = -1, i.e., at the zeros of z^4 + 1 = 0 (Fig. 9.7). Since all those poles lie
within C*, we may use either (9.9-1) or (9.9-4) in evaluating the integral.
First method. Applying (9.8-2) we have
z^3 + 2 ai + 2 1 1 1 1 1
Res --= --= - + - - = - - -ak
z=a1o z4 + 1 4ai 4 2 ai 4 2
Hence by (9.9-1),
--dz = 27ri """"' - - -ak
J
za + 2.
4
( 1 1 )
c+ z
4
+l f:i 4 2
= 27ri (1 - % t ak) = 27ri
k=l
since "E!=l ak = 0.
Second method. By using (9.7-4) we have
Hence by (9.9-4),
Fig. 9.7
Res za + 2 == -Res ~ 1 + 2z3 = -1
z=oo z^4 + 1 z=O z 1 + z^4
J
z: +
2
dz= -27ri(-1) = 27ri
z + 1
c+