Assembly Language for Beginners

(Jeff_L) #1

9.1. PRIMITIVE XOR-ENCRYPTION


29, 97, 122, 17, 15, 114, 110, 3, 5, 125, 125, 99, 126, 119, 102,
30, 122, 2, 117}, 1},
{{80, 1, 74, 59, 113, 45, 56, 86, 52, 91, 19, 64, 60, 60, 63,
25, 38, 59, 59, 42, 14, 53, 38, 77, 66, 38, 113, 38, 75, 4, 43, 84,
63, 101, 64, 43, 79, 64, 40, 57, 16, 91, 46, 119, 69, 40, 84, 117,
9, 97, 13, 99, 15, 119, 20, 105, 117, 98, 103, 118, 1, 126, 29,
97, 122, 17, 15, 114, 110, 3, 5, 125, 125, 99, 126, 119, 102, 30,
122, 2, 117}, 1},
{{80, 2, 74, 49, 113, 49, 51, 92, 39, 8, 92, 81, 116, 62, 57,
80, 46, 40, 114, 36, 75, 56, 33, 76, 9, 55, 56, 59, 81, 65, 45, 28,
60, 55, 93, 39, 90, 28, 124, 106, 16, 20, 104, 119, 8, 109, 26,
106, 9, 97, 13, 99, 15, 119, 20, 105, 117, 98, 103, 118, 1, 126,
29, 97, 122, 17, 15, 114, 110, 3, 5, 125, 125, 99, 126, 119, 102,
30, 122, 2, 117}, 1}}


Tally’s output is a list of pairs, each pair has 81-byte block and number of times it has been occurred in
the file. We see that the most frequent block is the first, it has been occurred 1739 times. The second
one has been occurred 1422 times. There are others: 1012 times, 377 times, etc. 81-byte blocks which
has been occurred just once are at the end of output.


Let’s try to compare these blocks. The first and the second. Is there a function in Mathematica which
compares lists/arrays? Certainly is, but for educational purposes, I’ll use XOR operation for comparison.
Indeed: if bytes in two input arrays are identical, XOR result is 0. If they are non-equal, result will be
non-zero.


Let’s compare first block (occurred 1739 times) and the second (occurred 1422 times):


In[]:= BitXor[stat[[1]][[1]], stat[[2]][[1]]]
Out[]= {0, 3, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, \
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, \
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, \
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0}


They are differ only in the second byte.


Let’s compare the second block (occurred 1422 times) and the third (occurred 1012 times):


In[]:= BitXor[stat[[2]][[1]], stat[[3]][[1]]]
Out[]= {0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, \
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, \
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, \
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0}


They are also differ only in the second byte.


Anyway, let’s try to use the most occurred block as a XOR key and try to decrypt four first 81-byte blocks
in the file:


In[]:= key = stat[[1]][[1]]
Out[]= {80, 103, 2, 116, 113, 102, 118, 25, 99, 8, 19, 23, 116, \
125, 107, 25, 99, 109, 114, 102, 14, 121, 115, 31, 9, 117, 113, 111, \
5, 4, 127, 28, 122, 101, 8, 110, 14, 18, 124, 106, 16, 20, 104, 119, \
8, 109, 26, 106, 9, 97, 13, 99, 15, 119, 20, 105, 117, 98, 103, 118, \
1, 126, 29, 97, 122, 17, 15, 114, 110, 3, 5, 125, 125, 99, 126, 119, \
102, 30, 122, 2, 117}


In[]:= ToASCII[val_] := If[val == 0, " ", FromCharacterCode[val, "PrintableASCII"]]


In[]:= DecryptBlockASCII[blk_] := Map[ToASCII[#] &, BitXor[key, blk]]


In[]:= DecryptBlockASCII[blocks[[1]]]
Out[]= {" ", " ", " ", " ", " ", " ", " ", " ", " ", " ", " ", " \
", " ", " ", " ", " ", " ", " ", " ", " ", " ", " ", " ", " ", " ", " \
", " ", " ", " ", " ", " ", " ", " ", " ", " ", " ", " ", " ", " ", " \
", " ", " ", " ", " ", " ", " ", " ", " ", " ", " ", " ", " ", " ", " \
", " ", " ", " ", " ", " ", " ", " ", " ", " ", " ", " ", " ", " ", " \
", " ", " ", " ", " ", " ", " ", " ", " ", " ", " ", " ", " ", " "}


In[]:= DecryptBlockASCII[blocks[[2]]]
Out[]= {" ", "e", "H", "E", " ", "W", "E", "E", "D", " ", "O", \
"F", " ", "C", "R", "I", "M", "E", " ", "B", "E", "A", "R", "S", " ", \

Free download pdf