Physics Times – July 2019

C D y 0.5dy 0

0.5 0.5

1 1

1

.

C D 2 4

W ydx dx



      

0.5

1 dx 4



  

E F y dy , 0, 0, WEF 0

F A x dx 0, 0, WF A  0

^

3

4 2 4

W

  

      

Given   1

 W 0.75J

5.Sol:

330 10 cos53 330 10

120

b 330 30 cos37 330

f

     

    

    

336 34

120 8.128

306 33

Hz

 

   

 

6.Sol:

3

2 2

s

c

T

 T

(^) Ts 3 Tc
1 3
3 1
c c c s
s s s c
l T l Y
l T l Y
       
      
       
5.Sol:
6.Sol:
11
11
2 10
2
1 10
  
 
  