Part B
AB 3. (a) At (2,5), so the tangent line is y − 5 = 4(x − 2).
Solving for y yields f (x) ≈ 5 + 4(x − 2).
(b) f (2.1) ≈ 5 + 4(2.1 − 2) = 5.4.
(c) The differential equation is separable:Since f passes through (2,5), it must be true that
Thus c = 9, and the positive root is used.
The solution is
(d)