Barrons AP Calculus - David Bock
dmanu
(dmanu)
2022-08-30 04:58:57 UTC
#1
(D) y ′ = ex · 1 + ex (x − 1) = xex;
y ′′ = xex + ex and y ′′(0) = 0 · 1 + 1 = 1.
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