Barrons AP Calculus - David Bock
dmanu
(dmanu)
2022-08-30 04:58:57 UTC
#1
(B) [f (x^3 )] ′ = f ′(x^3 )·3x^2 , so P ′(1) = f ′(1^3 )·3·1^2 = 2·3.
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