22.3. ENTANGLEDSTATESFOR”QUANTUMRADIO”? 353
Iftheright-handparticleisinstate|ψ>,theexpectationvalueforobservableQis
<ψ|Q|ψ>;whileiftheparticleisinstate|ψ′>,thevalueisis<ψ′|Q|ψ′>. After
manyruns,theaveragevalueobtainedmustbe
<Q> = Prob.tofind1R×<ψ|Q|ψ>+Prob.tofind1G×<ψ′|Q|ψ′>
= |cR|^2 <ψ|Q|ψ>+|cG|^2 <ψ′|Q|ψ′> (22.29)
whichisthesameasresult(22.26).ThereforeMarycan’ttellifJohnhadturnedon
hisdetector,iftheswitchsettingisat1. WhatifJohnsetstheswitchtosetting2?
Ingeneral,the”switch1”eigenstates{| 1 R>, | 1 G>}andthe”switch2”eigen-
states{| 2 R>, | 2 G>}aresimply differentbasisvectorsforthe left-handparticle
HilbertSpace,relatedbyaunitarytransformation
| 1 M>=
∑
M=R,G
UMN| 2 N> (22.30)
wherewerecallthattheunitarityproperty
δMN=
∑
J
UNJUM∗J (22.31)
followsfromorthonormality
δMN = < 1 M| 1 N>
=
∑
K
UM∗K< 2 K|
∑
J
UNJ| 2 J>
=
∑
J
UM∗JUNJ (22.32)
Wecanthereforewritetheentangledstate|Ψ>as
|Ψ> =
∑
M=R,G
[cRURM|ψ>r+cGUGM|ψ′>r]| 2 M>l
=
∑
M=R,G
bM| 2 M>l|φM>r (22.33)
where
bM|φM>≡cRURM|ψ>r+cGUGM|ψ′>r (22.34)
Then,afterJohnmakeshismeasurement,theparticleswillbe
eitherinstate | 2 R>|φR>, withprobability |bR|^2
orelseinstate | 2 G>|φG>, withprobability |bG|^2
(22.35)
Aftermanyruns,theexpectationvalueisfoundbyMarytobe
<Q> = Prob.tofind2R×<φR|Q|φR>+Prob.tofind2G×<φG|Q|φG>