360 CHAPTER23. THEPROBLEMOFMEASUREMENT
Theinterferencetermis
<AB>int=
∑
i(=j
c∗icj<ψi|A|ψj><φi|B|φj> (23.12)
anditisnonzeroprovidingthematrices
Aij≡<ψi|A|ψj> and Bij≡<φi|B|φj> (23.13)
arebothnon-diagonal.
Fromthisdiscussionweextractthefollowingconclusions:
1.Inprinciple,itisalwayspossibletodistinguishexperimentallybetweenamixture
andapurestate;
- Todistinguish betweenpureandmixedstatesofcompositesystems,onemust
makemeasurementsoneachofthecomponents.
Thus, tothequestion,”whatdoesameasurementdo?,”ourtentativeresponse
is: ”itleavesthemeasuredsysteminamixedstate.”Moreprecisely,ifthedetector
makes ameasurement ofobservable Qwhose eigenstates are{φi}, andifthe the
particleasitentersthedetectorisintheone-particlepure-state
ψ=
∑
i
ciφi (23.14)
thentheparticle,immediatelyafterdetection,willbeinthemixedstate
M={particleinoneofthestates φi withprobability |ci|^2 } (23.15)
23.2 The Problem of Measurement
Theproblemofmeasurementistheproblemthatnoclosedsystem,evolvingaccording
totheSchrodingerequation,canevermakeatransitionfromapurestatetoamixed
state.Ameasurement,aswehavedescribedit,canthereforeneveroccurifallrelevant
objects(thedetectoraswellasthedetectedobject)obeytheSchrodingerequation.
Inordertoexplainhowadetectorworks, onewouldbeginbyanalyzingthein-
teraction betweenthedetector andtheparticle, anddescribe theevolutionofthe
particle-detectorsystemintermsofsome(probablyverycomplicated)Hamiltonian,
involvingthedegreesoffreedomofboththeparticleandthedetector.Buttounder-
standwhythereisaproblemconnectedwiththemeasurementprocess,onedoesn’t
needtoknowanythingaboutthiscomplicatedHamiltonian. Itisenoughtosimply
assumethatanappropriateHamiltonianexistssuchthat,iftheparticlestartsoutin