Aptitude Test Problems in Physics Science for Everyone by S Krotov ( PDFDrive.com )

204 Aptitude Test Problems in Physics

condition of floating for the ball now becomes

Pot V = Pmer Pw (V — V1),

whence

Pst —Pw V.

Pmer—Pw

Thus, the ratio of the volumes of the parts of the

ball submerged in mercury in the former and latter

cases is

Vo = Pot Pmer Pw^ 1— Pw/Pmer

V1 Pmer Pot — Pw^1 -- Pw/Pst

Since pmer> Pot, Vo > VI, i.e. the volume of the

part of the ball immersed in mercury will become

smaller when water is poured.

1.109. The level of water in the vessel in which the

piece of ice floats is known to remain unchanged

Fig. 195.

after melting of ice. In the case under considera-
tion, we shall assume that the level of water at the
initial moment (measured from the bottom of the
vessel) is Ito, and that the level of the surface of
oil is h (Fig. 195). If the vessel contained only wat-
er, its level hl for the same position of the piece
of ice relative to the bottom of the vessel would
obey the condition

< hi < A.