Aptitude Test Problems in Physics Science for Everyone by S Krotov ( PDFDrive.com )

Solutions (^213)
to the triangle corresponding to the first cycle.
Therefore, the work A 2 done in the second cycle
will be
A2 — A1 (132 — P°)2
(PO — P1) 2 •
(The areas of similar triangles are to each other as
the squares of the lengths of the corresponding ele-
ments, in our case, altitudes.) The total work A
done during the cycle 1 - 4- 4 - 4-^3 - 4- 2 --•-^1 will
therefore be
A=A i^1 —(p2—pori ,, 750 J.
L (Po-Pir J
2.6. According to the first law of tnermodynamics,
the amount of heat AQ 1 received by a gas going

P

P 1

P2

Pt,

Vo iff V2

Fig. 199

over from state 1 (po , Vo ) to state 2 (pa , V 1 )

(Fig. 199) is

AQI = A Ui + Ai,

where A UIL is the change in its internal energy,

and A 1 is the work done by the gas,

Al_ (Po+ PO ( 171 — V 0)

2 •