Aptitude Test Problems in Physics Science for Everyone by S Krotov ( PDFDrive.com )

Solutions (^263)
and for the junction D
Is+Is =1 4 + Ib
will automatically be observed for the junctions E
and F (this is due to the equality of the resistances
Fig. 2
of all resistors of the circuit). Let us now write
Kirchhoff's second rule in order to obtain a system
of five independent equations:
( 1 4 + + R U,
(I s + 1 4 ) R 1 5 R,
(I 2 + 1) R I 2 R,
where R is the resistance of each resistor. Solving
this system of five equations, we shall express all
the currents in terms of / 1 :
„ 6 „ (^) /1 3
i a = -- • 1, /3= 5 5 / = I,
4 5 ..,
4
"=--^6. /^1.
Betlides,
U=( 11 + 11 +- 13 / 1 ) R.
Consequently, U/I^1 =R.