1.11. UNIFORM BENDING AND NONUNIFORM BENDING
Load
(kg)
Travelling Microscope
Readings
Elevation
for load
M= 0.05 kg
Load increasing(m) Load decreasing(m) Mean (m) (m)
L+ 0.05
L
L+ 0.10
L+ 0.15
L+ 0.20
L+ 0.25
Mean elevation (y) =
Figure 1.31:Uniform bending - Measurement of elevation at the mid point of the beam
callipers, the breadth (b) of the beam is determined. The thickness (d) of the beam is
measured using a screw gauge. Young’s Modulus of the beam is then calculated from the
expression:
Y =
3
2
M gal^2
bd^3 y
Self Learning Activity : Young’s Modulus Uniform Bending
Using the unifrom bending simulator, determine Young’s
moduli of the available materials.
http://vlab.amrita.edu/?sub=1&brch=280&sim=550&
cnt=1
Worked out Example 1.11.1
A rectangular bar 1m long, 2 cm broad, and 0.5 cm thick is supported symmetrically
on its flat face on two knife edges 70 cm apart. When loads of 200 g are hung from
the two ends, the elevation of the centre of the bar is 4.8 mm. Find the Young’s
modulus of the bar [ 6 ].
Solution:
The beam is bent uniformly because it is supported symmetrically and loaded at
its ends. For this beaml=0. 7 m anda= 0.15 m. Using the expression (1.39)we
calculate the Young’s Modulus of the beam.
Y =
3
2
M gal^2
bd^3 y
=
3(0. 2 kg)(9.8m/s^2 )(0.15m)(0.7m)^2
2(2◊ 10 ≠^2 m)(0. 5 ◊ 10 ≠^2 m)^3 (4. 8 ◊ 10 ≠^3 m)
=18.0GPa
1.11.2 Non-uniform Bending: Theory and Experiment
A beam is supported on two knife edges with a load applied midway between the supports,
as shown shown in Figure1.32, is an example of nonuniform bending [ 7 ]. Letlbe the