1.11. UNIFORM BENDING AND NONUNIFORM BENDING
lengthlbetween knife edges and suspend a loadLfrom the middle of the beam. A pin
is fixed vertically at the midpoint of the beam. Focus a travelling microscope to the tip
of the pin such that the horizontal cross-wire coincides with the image of pin-tip. Note
down the reading on the vertical scale of the microscope. Increase the load by adding 50
g. Lower the microscope such that the horizontal cross-wire now coincides with the new
position of pin tip image and note down the reading from vertical scale. This is repeated
by increasing the load in steps of 50 g tillL+250 gm and also for decreasing loads. The
readings are tabulated as shown (Figure1.34) and mean depression (y) for M= 0.05 kg
is calculated. Using a vernier calipers, the breadth (b) of the beam is determined. The
Load
(kg)
Travelling Microscope
Readings
Depression
for load
M= 0.05 kg
(m)
Load increasing(m) Load decreasing(m) Mean
(m)
L+ 0.05
L
L+ 0.10
L+ 0.15
L+ 0.20
L+ 0.25
Mean Depression (y) =
Figure 1.34: Non-Uniform bending - Measurement of depression at the mid point of the
beam
thickness (d) of the beam is measured using a screw gauge. Young’s Modulus of the beam
is then calculated from the expression:
Y=
Mgl^3
4 bd^3 y
Self Learning Activity : Young’s Modulus Non-uniform Bending
Using the non-unifrom bending simulator, determine Young’s
moduli of the available materials.
http://vlab.amrita.edu/?sub=1&brch=280&sim=1509&
cnt=1
Worked out Example 1.11.2
A 1 m bar with square cross-section of side 5 mm is supported horizontally at its
ends and is loaded with 100 g mass at the middle. The mid point is depressed by
1.96 mm due to the load. Calculate the Young’s Modulus of the material of the load.
Solution:
Since the beam is supported at its ends and loaded at the middle, its bending is
nonuniform. Length between supports (l) = 1 m. Square cross-section of side 5 mm
impliesb=d=0. 005 m. Depression at the mid point (y) = 1.96◊ 10 ≠^3 m. Mass