Everything Maths Grade 10

(Marvins-Underground-K-12) #1
Worked example 4: Angles of elevation and depression

QUESTION


A block of flats is 200 m away from a cellphone tower. Someone stands atB. They measure the angle from
Bto the top of the tower (E) to be 34° (the angle of elevation). They then measure the angle fromBto the
bottom of the tower (C) to be 62° (the angle of depression).


What is the height of the cellphone tower (correct to the nearest metre)?


C


D


A


B


E


34 ◦
62 ◦

200 m

Note: diagram not drawn to scale


SOLUTION


Step 1: To determine heightCE, first calculate lengthsDEandCD


△BDEand△BDCare both right-angled triangles. In each of the triangles, the lengthBDis known. Therefore
we can calculate the sides of the triangles.


Step 2: CalculateCD


The lengthACis given.CABDis a rectangle soBD=AC=200 m.


In△CBD:


tanCBD^ =

CD


BD


)CD=BDtanCBD^
= 200tan 62 °
=376,1452...
376 m

Step 3: CalculateDE


In△DBE:


tanDBE^ =

DE


BD


)DE=BDtanDBE^
= 200tan 34 °
=134,9017...
135 m

Step 4: Add the two heights to get the final answer


The height of the tower is:CE=CD+DE=135 m+376 m=511 m.


Chapter 11. Trigonometry 395
Free download pdf