Worked example 4: Angles of elevation and depression
QUESTION
A block of flats is 200 m away from a cellphone tower. Someone stands atB. They measure the angle from
Bto the top of the tower (E) to be 34° (the angle of elevation). They then measure the angle fromBto the
bottom of the tower (C) to be 62° (the angle of depression).
What is the height of the cellphone tower (correct to the nearest metre)?
C
D
A
B
E
34 ◦
62 ◦
200 m
Note: diagram not drawn to scale
SOLUTION
Step 1: To determine heightCE, first calculate lengthsDEandCD
△BDEand△BDCare both right-angled triangles. In each of the triangles, the lengthBDis known. Therefore
we can calculate the sides of the triangles.
Step 2: CalculateCD
The lengthACis given.CABDis a rectangle soBD=AC=200 m.
In△CBD:
tanCBD^ =
CD
BD
)CD=BDtanCBD^
= 200tan 62 °
=376,1452...
376 m
Step 3: CalculateDE
In△DBE:
tanDBE^ =
DE
BD
)DE=BDtanDBE^
= 200tan 34 °
=134,9017...
135 m
Step 4: Add the two heights to get the final answer
The height of the tower is:CE=CD+DE=135 m+376 m=511 m.
Chapter 11. Trigonometry 395