CHAPTER 2. LOGARITHMS 2.
The right hand side:
log 10− log 100 = 1− 2
=− 1
Both sides are equal. Therefore, log( 10010 ) = log 10− log 100.
Activity: Logarithm Law 4:loga
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x
y
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=loga(x)−loga(y)
Write as separate logs:
- log 2 (^85 )
- log 8 (^1003 )
- log 16 (xy)
- logz(^2 y)
- logx(y 2 )
2.9 Logarithm Law 5: loga(xb) = b loga(x)
EMCJ
Once again, we need torelate x to the base a. So, we let x = am. Then,
loga(xb) = loga((am)b)
= loga(am. b) (Exponential Law in Equation (Grade 10))
But, m = loga(x) (Assumption that x = am)
∴ loga(xb) = loga(ab .loga(x))
= b. loga(x) (Definition of logarithm in Equation 2.1)
For example, we can show that log 2 (5^3 ) = 3 log 2 (5).
log 2 (5^3 ) = log 2 (5. 5. 5)
= log 2 5 + log 2 5 + log 2 5 (∵ loga(x.y) = loga(am.an))
= 3 log 25
Therefore, log 2 (5^3 ) = 3 log 2 (5).
Activity: Logarithm Law 5:loga(xb)=bloga(x)
Simplify the following:
- log 2 (8^4 )
- log 8 (10^10 )
- log 16 (xy)
- logz(yx)
- logx(y^2 x)