3.6 CHAPTER 3. SEQUENCES AND SERIES
for an arithmetic sequence and sum it from i = 1 to any positive integer n:
�ni=1ai =�ni=1[a 1 +d (i− 1)]=
�ni=1(a 1 +di−d)=
�ni=1[(a 1 −d) +di]=
�ni=1(a 1 −d) +�ni=1(di)=
�ni=1(a 1 −d) +d�ni=1i= (a 1 −d)n +dn
2
(n + 1)=n
2
(2a 1 − 2 d +dn +d)=n
2
(2a 1 +dn−d)=n
2
[ 2a 1 +d (n− 1) ]So, the general formulafor determining an arithmetic series is given by
Sn=�ni=1[a 1 +d (i− 1) ] =
n
2[ 2a 1 +d (n− 1) ] (3.25)For example, if we wishto know the series S 20 for the arithmetic sequence ai= 3 + 7 (i− 1), we
could either calculate each term individually andsum them:
S 20 =
�^20
i=1[3 + 7 (i− 1)]= 3 + 10 + 17 + 24 +31 + 38 + 45 + 52 +
59 + 66 + 73 + 80 + 87+ 94 + 101 +
108 + 115 + 122 + 129+ 136
= 1390or, more sensibly, we could use Equation (3.25)noting that a 1 = 3, d = 7 and n = 20 so that
S 20 =
�^20
i=1[3 + 7 (i− 1)]=^202 [2. 3 + 7 (20− 1)]
= 1390
This example demonstrates how useful Equation(3.25) is.
Exercise 3 - 3
- The sum to n terms of an arithmetic series is Sn=
n
2
(7n + 15).(a) How many terms ofthe series must be addedto give a sum of 425?
(b) Determine the 6 thterm of the series.- The sum of an arithmetic series is 100 times its first term, while the last term is 9 times the first
term. Calculate the number of terms in the series if the first term is not equal to zero.