- T, F Again, divide and conquer. Is the first statement true or false? It’s
tricky but true. For each mole of original solute, a nonionic solute
produces only 1 mole of particles in solution. One mole of NaCl,
however, dissociates into 2 moles of particles. So the number of
particles floating around in the NaCl solution will be twice the
number of moles in the nonionic solution. The freezing point
depression for the nonionic solution will be one half what it is for the
NaCl solution.
What about the second statement? It’s false. The
freezing point depression constant does vary with the
solvent. - B You’ve learned to associate increased temperature with increased
solubility of solids in water. This question is simple, and (B) is correct. - E The question is about solutions that are capable of conducting
electricity. Think of electrolytes, and remember that you should associate
them with “ions in solution.” Which of the answer choices lists an ionic
compound capable of dissociating in solution? (E) does. Ca is a metal and
Cl is a nonmetal, which tells you that CaCl 2 is most likely an ionic
substance. Choice (E) is the correct answer. - A This question asks you to look for the insoluble product of this
precipitation reaction. Because precipitations occur through double
replacement reactions, the two products formed will be NaCl(aq) and
BaSO 4 (s). If you look back at the solubility rules, you can see that sodium
chloride will be soluble; this means that you can eliminate this answer
choice, which leaves you with the correct answer, (A).
marvins-underground-k-12
(Marvins-Underground-K-12)
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