21.7 CHAPTER 21. MOTION IN ONE DIMENSION
- its acceleration
- its final velocity
- at what time the motorcycle had covered half the total distance
- what distance the motorcycle had covered in half the total time.
SOLUTION
Step 1:Identify what information is given and what is asked for
We are given:
~vi = 0m·s−^1 (because the object starts from rest.)
∆~x = 64m
t = 4s
~a =?
~vf =?
t = ?at half the distance∆~x= 32 m.
∆~x = ?at half the timet= 2 s.
All quantities are in SI units.
Step 2:Acceleration: Find a suitable equation to calculate the acceleration
We can use Equations 21.3
∆~x=~vit+^12 ~at^2
Step 3:Substitute the values and calculate the acceleration
∆~x = ~vit+^12 ~at^2
64 m = (0 m·s−^1 × 4 s) +^12 ~a×(4s)^2
64 m = (8s^2 )~a
~a = 8 m·s−^2 East
Step 4:Final velocity: Find a suitable equation to calculate the final velocity
We can use Equation 21.1 - remember we now also know the acceler-
ation of the object.
~vf=~vi+~at
428 Physics: Mechanics