11.7 CHAPTER 11. VECTORS
H
3 cm = 6 kmA
6 cm = 12 km BC
2,25 cm = 5,5 km? 4,6 cm = 9,2 kmNSW EStep 7 : Apply the scale conversion
We now use the scale toconvert the length of theresultant in the scale diagram
to the actual displacement in the problem. Sincewe have chosen a scaleof 1 cm
= 2 km in this problemthe resultant has a magnitude of 9,2 km. The direction
can be specified in terms of the angle measuredeither as 072,3◦east of north or
on a bearing of 072,3◦.Step 8 : Quote the final answer
The resultant displacement of the ship is 9,2 kmon a bearing of 072,3◦.Example 3: Head-to-Tail GraphicalAddition II
QUESTIONA man walks 40 m East,then 30 m North.- What was the total distance he walked?
- What is his resultantdisplacement?
SOLUTIONStep 1 : Draw a rough sketchresultant40 m30 m NSW EStep 2 : Determine the distancethat the man travelled
In the first part of his journey he travelled 40 m and in the second part hetravelled
30 m. This gives us a total distance travelled of40 m + 30 m = 70 m.Step 3 : Determine his resultant displacement