account for the stretched
distance.
The net force on the block is
F = k(d + y) − mg
but this equation becomes F = ky because kd = mg (as we saw above).
Since the resulting force on the block, F = ky, has the form of Hooke’s law, we
know that the vertical simple harmonic oscillations of the block have the same
characteristics as do horizontal oscillations, with the equilibrium position, y = 0,
not at the spring’s natural length, but at the point where the hanging block is in
equilibrium.
Questions 9-12
A block of mass m = 1.5 kg is attached to the end of a vertical
spring of force constant k = 300 N/m. After the block comes to
rest, it is pulled down a distance of 2.0 cm and released.
- How far does the weight of the block cause the spring to stretch
initially? - What are the minimum and maximum amounts of stretch of the
spring during the oscillations of the block? - At what point(s) will the speed of the block be zero?
- At what point(s) will the acceleration of the block be zero?
Here’s How to Crack It
- The weight of the block initially stretches the spring by a distance of