So the image is located 40 cm from the lens, on the opposite
side from the object.
- Because si is positive, the image is real.
- Real images are inverted.
- The magnification is
(The fact that the magnification is negative confirms that the
image is inverted.) The height of the image is
h 1 = |m| • b 0 = 1(10 cm) = 10 cm
These results are illustrated in Question 24.
Questions 31-34
An object of height 9 cm is placed 48 cm in front of a diverging lens
with a focal length of −24 cm.
What Produces What?
Only converging lenses
can produce real images
(if s 0 ≽ f). Diverging
lenses can only produce
virtual images.
- Where’s the image?
- Is it real or virtual?
- Is it upright or inverted?
- What’s the height of the image?
