Cracking the SAT Physics Subject Test

(Marvins-Underground-K-12) #1
to the impulse, which is the area under the force versus time graph. The
region under the graph from t = 0 to t = 0.4 sec is composed of a right
triangle (from t = 0 to t = 0.2 sec) plus a rectangle (from t = 0.2 sec to t = 0.4
sec), so the total area under the graph from t = 0 to t = 0.4 sec is (1/2)(0.2)
(100) + (0.4 − 0.2)(25) = 10 + 5 = 15 kg·m/sec.


  1. B Apart from sign, the magnification factor, m, is equal to i/o, where i is the
    image distance from the lens and o is the object distance. In this case then,
    we have m = i/o = (8 cm)/(20 cm) = 2/5.

  2. C The nth harmonic frequency is equal to n times the fundamental frequency,
    f 1. Therefore

  3. C If both the source and detector travel in the same direction and at the same
    speed, there will be no relative motion and hence no Doppler shift.

  4. C In a single medium, a wave travels a consistent speed. The frequency does
    not change, so the wavelength must change (because the wave speed
    changes).

  5. E Gamma rays and X-rays are very high-energy, short-wavelength radiations.
    Ultraviolet light has a higher energy and shorter wavelength than visible
    light. Within the visible spectrum, the colors are—in order of increasing
    frequency—ROYGBV, so orange light (“O”) has a lower frequency—and
    thus a longer wavelength—than blue light (“B”).

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