Algebra Demystified 2nd Ed

Chapter 5 e X P O N e N T S a N D r O O T S 121

DeMYSTiFieD / algebra DeMYSTiFieD / HuttenMuller / 000-0 / Chapter 5

The root minus the power is 4 – 3 = 1, so we need another x^1 under the root.

4883 8

4 1

4 1

4

4 4

4

x

x

x

x

x

x

x

⋅==

Rationalize the denominator.

54 x 2
x

The root minus the power is 5 – 2 = 3, so we need another x^3 under the root.

5442 4 4

5 3

5 3

5 3

5 5

x^5353

x

x

x

xx

x

xx

x

⋅ ===x

7 223 22

7

7 3

7 4

7 4

7 4

7 7

7 4

x x

x

x

x

x

x

x

=⋅==

1
2

1

2

2

2

2

2

4

(^332)
3 2
3 2
3 22
3 3
3 2
xx
x
x
x
x
x
x
=⋅()==
() ()
yy yy
(^93)
3
3
27
3
27
(^5523)
5 3
5 3
5
5 5
5
=⋅==
4222 4 2 22
4 32
4 32
4 32
4 44
4 32
xy xy^44
xy
xy
xy
xy
xy
xy
=⋅==
()
==^2
(^4) xy^32
xy
PRACTICE
Rationalize the denominator.

1. 362
   x
   2.^532
   3.^1

(^5) ()x− 42

4. x

(^4) x
PRACTICE
Rationalize the denominator.
PRACTICE
Rationalize the denominator.