Algebra Demystified 2nd Ed

(Marvins-Underground-K-12) #1

426 algebra De mystif ieD


✔SOLUTIONS



  1. The area formula for a triangle is AB = ^12 H. The area is 12. The length of
    its base is two-thirds its height, so BH = ^23. The formula becomes
    12 1
    2


2
3

 =  HH







.

12 1
2

2
3
12 1
2

2
3
12 1
3
312
36
6

2

2

2
2

=






=⋅

=

=
=
=

HH

H

H

H
H

()

HH

The height of the triangle is 6 inches. Its base is ()^2364  =  inches.


  1. The formula for the area of a triangle is AB =  21 H. The area is 20. The
    height is 3 cm more than the base, so H = B + 3. The formula becomes
    20  (=  21 BB )+  3.


20 1
2

3
2203
40 3
40 3
03

2
2

=+
=+
=+
=+
=+

BB
BB
BB
BB
BB

()
() ()
()

−−
=− +

40
05 ()()BB 8

B − 5 = 0 B + 8 = 0 (This does not lead to a solution.)
B = 5
The triangle’s base is 5 cm and its height is 5 + 3 = 8 cm.


  1. The formula for the area of a triangle is AB =  21 H. The area is 20. The
    equation B + H = 14 gives us so H = 14 − B. The formula becomes
    20  (=  21 BB 14  )– .

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