438 algebra De mystif ieD
✔SOLUTIONS
- Let t represent the number of hours each has traveled. The plane’s
distance after t hours is 200t and the car’s distance is 45t.
a = 45t
b = 200tc =164 (45t) 2 a+ (200^2 + b^2 t= ) 2 c= 164^22
FIGURE 11-6
()()
,,
,
45 200 164
2025 40 000 26 896
42 025
222
22
tt
tt
+=
+=
tt
t
t
t
2
2
26 896
26 896
42 025
26 896
42 025
080
=
=
=
=
, , , , ,.
The car and plane will be 164 miles apart after 0.80 hours or 48 minutes.