1001 Algebra Problems.PDF

606.Simplify: ( 3 +  7 )(2 3 – 5 7 )
a.–29 – 3 21 
b.–29 + 3 21 
c.29 – 3 21 
d.–29 – 3 21 

607.Simplify:

a.

b.–

c.

d.–

608.Simplify by rationalizing the denominator:

a.–

b.

c.

d.

Set 39 (Answers begin on page 219)

This problem set focuses on solving equations involving
radicals.

609.Solve:7 + 3x= 4
a. 3
b.–3
c. 3 i
d.There is no solution.

610.Solve: 4 x+ 33= 2x– 1
a. 4
b.–2
c.–2 and 4
d.There is no solution.

611.Ifa =6, then a =

a. 3 

b. 6 

c. 3  6 

d. 6  6 

e. 36

612.Ifp

4

= q–2= – ^13 , which of the following is

a possible value ofp?

a.–^13 

b.^19 

c.^13 

d. 3

e. 9

613.Solve:^35 x– 8= 3

a. 49

b.–7

c. 7 i

d.–7

614.Solve:^3 7 – 3x= –2

a.–5

b. 5

c. 5 i

d.–5i

615.Solve: (x–3)^2 = –28

a. 3  2 i 7 

b.–3 2 i 7 

c. 2  3 i 7 

d.–2 3 i 7 

616.Solve:10 – 3x= x– 2

a.–2

b.–2 and –3

c. 3

d.There is no solution.

^23 ^43

(^2)  2 x+ 6x
4 – 9x
(^2)  2 x– 6x
4 – 9x
 2 x+ 2x
2 – 3x
^2 ^2 x+6x
4 + 9x
^2 x
2 –3x
3 + 5^2 
41
3 + 5 2 
41
3 – 5^2 
41
3 –5 2 
41
^1
3 – 5 2 

• RADICAL EXPRESSIONS AND QUADRATIC EQUATIONS–